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Solve this equation for x: $&2x^2 + 12x - 7 = 0$&
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$$2x^2 + 12x - 7 = 0$$
$$2x^2 + 12x = 7$$
$$2(x^2 + 6x) = 7$$
$$2(x^2 + 6x + 9) = 7 + 18$$
$$2(x + 3)^2 = 25$$
$$(x + 3)^2 = 12.5$$
$$(x + 3) = \pm\sqrt {12.5}$$
$$x = -3 \pm\sqrt {12.5}$$