$$ \definecolor{crimBlue}{rgb}{0.196,0.467,0.533} \definecolor{crimOrange}{rgb}{0.969,0.553,0.149} \definecolor{crimGreen}{rgb}{0.498,0.694,0.302} $$
Evaluate the expression: $&3(x-1)^2 + 2x-7$& when $&{\color {crimOrange}x} = {\color{crimOrange}3}$&

Step 1: What is the first step for evaluating this expression?

Step 2: Parentheses: 3 – 1 =

Step 3: Exponent: (2)2 =

Step 4: Multiply: 3 × 4 = and 2 × 3 =

Step 5: Add 12 + 6 =

Step 6: Subtract 18 – 7 =

$$= 3({\color {crimOrange}3}-1)^2+2({\color {crimOrange}3})-7$$
$$= 3({\color {crimOrange} 3-1})^2+2(3)-7$$
$$= 3(3-1)^2+2(3)-7$$
$$= 3({\color {crimOrange}2})^2+2(3)-7$$
$$= 3{\color {crimOrange} (2)^2}+2(3)-7$$
$$= 3(2)^2+2(3)-7$$
$$= 3\cdot{\color{crimOrange}4}+2(3)-7$$
$$= {\color{crimOrange}3\cdot4}+{\color{crimBlue}2(3)}-7$$
$$= 3\cdot4+2(3)-7$$
$$= {\color{crimOrange}12}+{\color{crimBlue}6}-7$$
$$= {\color{crimOrange}12+6}-7$$
$$= 12+6-7$$
$$= {\color{crimOrange} 18}-7$$
$$= {\color {crimOrange} 18-7}$$
$$= 18-7$$
$$= {\color {crimOrange}11}$$