1. ∠KJL intercepts #& \overset{\frown}{\sf KL}#&
1. given
2. ∠KML intercepts #& \overset{\frown}{\sf KL}#&
2. given
3. m∠KJL = #&\frac{1}{2}(m\overset{\frown}{\sf KL})#&
3. ♣
4. m∠KML = #&\frac{1}{2}(m\overset{\frown}{\sf KL})#&
4. ♦
5. m∠KJL = m∠KML
5. ♠